![]() SUART.write(x) // SUART.write(*ptr) value is being transmitted over soft serial port **(1)** Get the address of the 1st location of the array of Fig-1 into pointer variable (ptr) and then read the value and then transmit it.īyte ptr = (byte) &data //we want to increment the pointer variable by 1-bye positionīyte x = *ptr //x receives the content of location m0, which is CD **2.** The value of the 1st byte (content of memory location m0) of Fig-1 can be known by executing the following codes: !(upload://wz2pPn219cBFxBHXKq4wFS5ihis.png) In response to this declaration: float data[2 =, the compiler creates the following 8-byte wide memory space (array) to hold the binar圓2 formatted bytes for the given float numbers. Should have the number of bytes to be written as well as the address of the buffer. -converting binar圓2 formatted bytes into float using union-įor (byte i = 4, j=0 i < 8, j<4 i++, j++) SUART.begin(9600) //Bd (Baud Rate) between UNO and NANOīyte *ptr = (byte*)&data //pointer will increase by 1-byte positionīyte m = SUART.readBytes(rxData, 8) //built-in code: if(SUART.available()>0) Serial.begin(9600) //bit transfer rate (Bd) between PC and UNO SoftwareSerial SUART(10, 11) //DPin-10 = SRX DPin-11 = STX MEGA Sender Codes: using SUART.write() method #include If OP is to use write() method, then the directive of your Post#3 is an approach on which the following Solution-2 is based upon. ![]() The OP is looking for a solution using WRITE.
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